> 数学 >
因式分解x2+4xy-4y2 x2-2(根号2)x-3
人气:197 ℃ 时间:2020-04-19 21:51:44
解答
x2+4xy-4y2
=(x^2+4xy+4y^2)-8y^2
=(x+2y)^2-8y^2
=(x+2y+2√2y)(x+2y-2√2y)
x2-2(根号2)x-3
=x^2-2√2x+2-5
=(x-√2)^2-5
=(x-√2+√5 )=(x-√2-√5)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版