弧长为C=6米,弧高为H=0.3米,弦长L怎么求?弧半径为R,弧所对的圆心角为A.Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*RnR0=15R1=14.949R2=14.95R3=14.95R=14.95米A=C/R=6/14.95=0.401338弧度=0.401338*...