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设cos=-3/5,求(tanαcos^3(α))/(1-sinα)
人气:473 ℃ 时间:2020-06-22 13:24:03
解答
设cosα=-3/5,求(tanαcos^3(α))/(1-sinα)因为:cosα=-3/5所以:sinα=(1-cos^2(α))^0.5=(1-9/25)^0.5=(16/25)^0.5=4/5 (tanαcos^3(α))/(1-sinα)=(sinαcos^2(α))/(1-sinα)=(sinα(1-sin^2(α)))/(1-sin...
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