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a(x^my^4)/(3x^2y^n)^2=4x^2y^2.求a.m.n的值.
人气:108 ℃ 时间:2020-05-17 13:05:43
解答
a(x^my^4)/(3x^2y^n)^2
=a(x^my^4)/(9x^4y^2n)
=(a/9)*x^(m-4)*y^(4-2n)
=4x^2y^2
所以a/9=4,m-4=2,4-2n=2
所以a=36,m=6,n=1
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