(x−2)(x−3)−(x−1)(x−4) |
(x−1)(x−3) |
(x−6)(x−7)−(x−5)(x−8) |
(x−5)(x−7) |
即
2 |
x2−4x+3 |
2 |
x2−12x+35 |
∴x2-4x+3=x2-12x+35,
移项合并得:8x=32,
解得:x=4,
经检验x=4是分式方程的解.
x−2 |
x−1 |
x−4 |
x−3 |
x−6 |
x−5 |
x−8 |
x−7 |
(x−2)(x−3)−(x−1)(x−4) |
(x−1)(x−3) |
(x−6)(x−7)−(x−5)(x−8) |
(x−5)(x−7) |
2 |
x2−4x+3 |
2 |
x2−12x+35 |