1.若1/a-1/b=3,分式(2a+3ab-2b)/(a-2ab-b)的值为__.
2.x/2=y/3,分式(7x²-y²)/(x²-2xy+3y²)的值是?
人气:146 ℃ 时间:2020-04-08 13:58:54
解答
1.若1/a-1/b=3,分式(2a+3ab-2b)/(a-2ab-b)的值为_3/5_.
(2a+3ab-2b)/(a-2ab-b)上下同除以ab
(2/b+3-2/a)/(1/b-2-1/a)=-3/(-5)=3/5
2.x/2=y/3,分式(7x²-y²)/(x²-2xy+3y²)的值是?(要过程)
x/2=y/3,则x/y=2/3
(7x²-y²)/(x²-2xy+3y²)上下同除以y²,(7 x²/ y²-1)/ (x²/ y²-2x/y+3)=(7*4/9-1)/(4/9-2*2/3+3)=19/19 =1
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