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lg25+lg2lg50+(lg2)的值
(lg2)的平方
人气:268 ℃ 时间:2020-04-11 13:11:17
解答
lg25 + lg2*lg50 + (lg2)^2
= lg25 + lg2*(1 + lg5) + (lg2)^2
= lg25 + lg2 + lg2*lg5 + lg2*lg2
= (lg25 + lg2) + lg2(lg5 + lg2)
= lg50 + lg2
= lg100
= 2
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