∵x²-3x+1=0
∴x²+1=3x
(x²+1)×1/x=3x×1/x
x²×1/x+1×1/x=3
∴x+(1/x)=3
∴[x+(1/x)]²=3²
x²+2×x×1/x+(1/x²)=9
x²+2+(1/x²)=9
∴x²+(1/x²)=9-2=7