已知弧长C=6米,弦长L=4.2米,求半径R和高H?
弧所对的圆心角为A.
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=2
R1=2.1113
R2=2.1271
R3=2.1274
R4=2.1274米
R=2.1274
A=C/R=6/2.1274=2.820344弧度=2.820344*180/π=161.594度
H=R-R*COS(A/2)=2.1274-2.1274*COS(161.594/2)=1.7872米