m^2-m-1=0,n^2-n-1=0由题意知m,n为方程x^2-x-1=0的两个不同的实根.由韦达定理知m+n=1,mn=-1m^2+n^2+2mn=(m+n)^2m^2+n^2=1+2=3(m^2+n^2)^2=m^4+2(mn)^2+n^49=m^4+n^4+2m^4+n^4=7(m^2+n^2)(m+n)=m^3+mn^2+m^2n+n^33=m^...