lim(n→∞){2^n[sin(x/2^n)]}求详细过程,谢谢!_数学解答

lim(n→∞){2^n[sin(x/2^n)]}
求详细过程,谢谢!

人气：479 ℃　时间：2020-04-30 20:15:51

解答

n→∞,2^n→∞
lim(n→∞){2^n[sin(x/2^n)]}
=lim(t→∞){t[sin(x/t)]}
=lim(t→∞)[sin(x/t)]/(1/t)
=x