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常微分方程的一道题(x-y-1)dx+(4y+x-1)dy=0
如题〒_〒
人气：453 ℃ 时间：2020-04-14 06:04:30
解答
解
(x-y-1)dx+(4y+x-1)dy=0
xdx-dx-(ydx+xdy)+4ydy-dy=0
两边积分
1/2x^2-x-xy+2y^2-y=C
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