sin^8X+cos^8X+4sin^2Xcos^2x-2sin^4xcos^4X(化简）
人气：407 ℃ 时间：2020-04-11 11:37:07
解答
原式=sin^8X-2sin^4xcos^4X+cos^8X+4sin^2Xcos^2x=（sin^4x-cos^4x）^2+4sin^2Xcos^2x=[（sin^2x-cos^2x）（sin^2x+cos^2x）]^2+4sin^2Xcos^2x=（sin^2x-cos^2x）^2+4sin^2Xcos^2x=sin^4x-2sin^2Xcos^2x+cos^4x+4sin...
推荐
猜你喜欢
