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计算:x-3分之x的平方-3-x分之2x-3+3-x分之2x+6
人气:413 ℃ 时间:2020-01-26 21:11:20
解答
x^2/(x-3)-(2x-3)/(3-x)+(2x+6)/(3-x)
=x^2/(x-3)+(2x-3)/(x-3)-(2x+6)/(x-3)
=[x^2+(2x-3)-(2x+6)]/(x-3)
=(x^2 -9)/(x-3)
=[(x+3)*(x-3)]/(x-3)
=x+3
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