x^2+y^2+2x-2y+1=0等价于(x+1)^2+(y-1)^2=1,圆心为(-1,1),它关于直线x-y+3=0对称的圆心为(2,-2),圆的半径不变仍为1,所求图形方程为:(x-2)^2+(y+2)^2=1