当n=1时,3^n-2^n=1,(n-2)2^n+2n^2=-2+2=0,前者大；当n=2时,3^n-2^n=5,(n-2)2^n+2n^2=8,前者小；当n=3时,3^n-2^n=19,(n-2)2^n+2n^2=26,前者小；设n=k,k≥2时,前者小,则3^k-2^k-(k-2)2^k+2k^2=3^k-(k-1)2^k+2k^2＜0当n...