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x的平方+xy-2(y的平方)-x+4y-2因式分解
这么求啊?x的平方+xy-2(y的平方)-x+4y-2具体的过程 谢谢了我感觉很难
人气:487 ℃ 时间:2020-03-25 04:28:43
解答
x²+xy-2y²-x+4y-2
=x²-2xy+y²+3xy-3y²-x+4y-2
=(x-y)²+3y(x-y)-x+4y-2
=(x-y)(x-y+3y)-x+4y-2
=(x-y)(x+2y)+x+2y-2x+2y-2
=(x-y+1)(x+2y)-2x+2y-2
=(x-y+1)(x+2y)-2(x-y+1)
=(x-y+1)(x+2y-2)
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