∵y=2x²-2x+3/x²-x+1∴yx²-yx+y=2x²-2x+3(y-2)x²+(2-y)x+(y-3)=0易知y≠2∴判别式=y²-4y+4-4y²+20y-24=-3y²+16y-20≥0∴2≤y≤10/3∴2