1) x²-5x = (x-5)²∴(x²-5x) = x(x-5) = (x-5)²∴ 5 (x-5) = 0∴ x=52) x²-5x-6=0left = (x-6)(x+1) = 0∴ x=6 or x=-13) 3x(x-2)=2(2-x)3x(x-2) - 2(2-x) = 0∴ (3x+2)(x-2) = 0x=-2/3 or...