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设x,y属于R*,且xy-(x+y)=1,则
A.x+y>=(2根号2)+2 B.xy
人气:466 ℃ 时间:2020-05-10 21:11:48
解答
A
xy≤[(x+y)/2]^2
xy-(x+y)=1
xy=(x+y)+1
x+y+1≤[(x+y)/2]^2
x,y属于R*
x+y>=(2根号2)+2
B,D错误原因如下:
x+y≥2根号xy
xy-(x+y)=1
x+y=xy-1
xy-1≥2根号xy
xy≥3+2根号2
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