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数学
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化简:7y/2x*根号下(1/y^2)-(x/y^3) 且(y>x>0) y/(3x-y)*根号下(9x^3y-6x^2y^2+xy^3)/y^2 且(3x>y>0)
化简:7y/2x*根号下(1/y^2)-(x/y^3) 且(y>x>0)
y/(3x-y)*根号下(9x^3y-6x^2y^2+xy^3)/y^2 且(3x>y>0)
人气:100 ℃ 时间:2019-08-22 14:11:24
解答
7y/2x*根号下(1/y^2)-(x/y^3) 且(y>x>0)
=7y/2x*1/y√(1-x/y)
=7/2x√(y-x)/y
=7/2xy√(y²-xy)
y/(3x-y)*根号下(9x^3y-6x^2y^2+xy^3)/y^2 且(3x>y>0)
=y/(3x-y)*1/y√(9x³y-6x²y²+xy³)
=1/(3x-y)√xy(9x²-6xy+y²)
=1/(3x-y)√xy(3x-y)²
=1/(3x-y)*(3x-y)√xy
=√xy
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