[(2^x+3^x+6^x)/3]^1/sinx=[1+(2^x+3^x+6^x-3)/3]^[3/(2^x+3^x+6^x-3)*(1/sinx)*(2^x+3^x+6^x-3)/3]原式=e^lim(2^x+3^x+6^x-3)/3sinx=e^lim(2^xln2+3^xln3+6^xln6)/3cosx=e^[(ln2+ln3+ln6)/3]=³√36