> 数学 >
x−y=
2
−1
xy=
2
,则代数式(x-1)(y+1)的值等于 ______
人气:386 ℃ 时间:2019-08-19 04:45:18
解答
(x-1)(y+1)
=xy+x-y-1
=xy+(x-y)-1
x−y=
2
−1
xy=
2
代入上式得:
=
2
+
2
-1-1
=2
2
-2
故答案为2
2
-2
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