lim(x-->0) (x - sinx)/[xln(1 + x²)]= lim(x-->0) 1/[(x - sinx)⁻¹xln(1 + x²)]= lim(x-->0) 1/[ln(1 + x²)^(x/(x - sinx))]= 1/[lim(x-->0) ln(1 + x²)^(1/x² · x³/(x ...