一道数学题( k=a/b+c=b/c+a=c/a+b;求k)快!
人气：264 ℃ 时间：2019-11-09 02:18:28
解答
k=a/(b+c)=b/(c+a)=c/(a+b)
(1)当a+b+c不=0 时.
k=a/(b+c)=b/(a+c)=c/(a+b)
=(a+b+c)/[(b+c)+(a+c)+(a+b)]
=(a+b+c)/(2a+2b+2c)
=1/2
(2)当a+b+c=0 时.
a=-(b+c),b=-(a+c),c=-(a+b),
k=a/(b+c)=b/(a+c)=c/(a+b)
=-1
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