x²+5xy-2x+3y+1=0(1) (1)×3-(2)得x+y-1=0x=1-y (3)把(3)代入(1)得1-2y+y²+5y-5y²-2+2y+3y+1=0-4y²+8y=0y=0y=2把y=0,y=2代入(3)得x=1或x=-1∴x=1 x=-1 y=0...