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化简,(4a-2b+3c)^2-(4a+2b-3c)^2
人气:281 ℃ 时间:2020-05-09 06:49:02
解答
(4a-2b+3c)^2-(4a+2b-3c)^2
=[(4a-2b+3c)+(4a+2b-3c)][(4a-2b+3c)-(4a+2b-3c)]
=8a*(-4a+6c)
=-32a^2+48ac
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