>
数学
>
x2-4x+y2+6y+13=0,
人气:127 ℃ 时间:2020-04-04 12:18:03
解答
即(x²-4x+4)+(y²+6y+9)=0
(x-2)²+(y+3)²=0
平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立.
所以两个都等于0
所以x-2=0,y+3=0
x=2,y=-3
推荐
已知x2-4x+y2+6y+13=0,求x-y的值
1.已知X2+Y2-4X-6Y+13=0,求Y2-X2的值
x2+4x+y2-6y+13=0 xy等于几?
已知x2+y2+4x-6y+13=0
已知x2+y2-4x+6y+13=0,求x和y的值分别是多少?
两数和为3,积为-10 求这两个数
用英语简单描写你的房间
以我的卧室写一篇英语作文
猜你喜欢
carefully
After paying 1000 dollars ____,you will all become full memebers of our club A each B all c every
Our class has a map of the world (改为同义句)
The baby didn't cry any more when she saw her mother.同义句
How do you go to school,on foot or by bus?
时间旅行的悖论
设f(x)=ax7+bx5+cx3+dx+5,其中a,b,c,d为常数.若f(-7)=-7,则f(7)=_.
计算1-3+5-7+9-11+…+97-99.
© 2024 79432.Com All Rights Reserved.
电脑版
|
手机版