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计算a+b+2根号ab/根号a+根号b-a根号b-b根号a/根号ab
人气:469 ℃ 时间:2020-03-29 03:10:25
解答
(a+b+2√ab)/(√a+√b)-(a√b-b√a)/√(ab)
=(√a+√b)^2/(√a+√b)-√(ab)(√a-√b)/√(ab)
=(√a+√b)-(√a-√b)
=√a+√b-√a+√b
=2√b
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