> 数学 >
椭圆x2/a2+y2/b2=1(a>b>0)与x轴正向交与A,若若这个椭圆上总存P,使OP垂直AP求离
人气:343 ℃ 时间:2020-05-23 21:49:18
解答
设:O(0,0),A(a,0),P(acost,bsint),t≠0
OP⊥AP--->(acost,bsint)•(acost-a,bsint) = 0
    即 a²(cos²t-cost)+b²sin²t
    = a²cos²t-a²cost+(a²-c²)sin²t
    = a²-a²cost-c²(1-cos²t)
    = c²cos²t-a²cost+(a²-c²)=0
--->e²cos²t-cost+(1-e²)=0
--->(cost-1)[e²cost-(1-e²)]=0
∵cost≠1--->-1≤cost=1/e²-1≤1--->0≤1/e²≤2
--->1/2≤e²<1--->√2/2≤e<1
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版