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若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值
人气:349 ℃ 时间:2019-11-17 04:52:24
解答
x+y=5xy
(2x-3xy+2y)/(x+2xy+y)
=[2(x+y)-3xy]/[(x+y)+2xy]
=(2×5xy-3xy)/(5xy+2xy)
=7xy/7xy
=1若x+1/x=3,求(x^4+x^2+1)/x^2的值.(x+1/x)²=x²+2+1/(x²)=9x²+1/(x²)=9-2=7你可以把(x^4+x²+1)/x²=x²[x²+1+1/(x²)]/x²约掉x²等于x²+1+1/(x²)=7+1=8希望采纳,不懂请追问!谢谢!
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