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解方程(m-5)x平方+2(m-5)x+1=0(m不等于5)
人气:314 ℃ 时间:2020-01-28 00:17:58
解答
(m-5)x^2+2(m-5)x+1=0x^2+2x+1/(m-5)=0x^2+2x+1-1+1/(m-5)=0(x+1)^2-(m-6)/(m-5)=0{x+1-√[(m-6)/(m-5)]}{x+1+√[(m-6)/(m-5)]}=0x=√[(m-6)/(m-5)]-1或x=√[(m-6)/(m-5)]-1
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