都要公式法
-1/2 x^2-3x+6=0
x^2=2(x+1)
4y^2 -(√2+8)y+ √2=0
0.09y^2-0.21y+0.1=0
人气:186 ℃ 时间:2020-04-12 20:00:57
解答
-1/2 x^2-3x+6=0x²+6x-12=0∴x=(-6±√84)/2∴x=-3+√21 x=-3-√21x^2=2(x+1)x²-2x-1=0∴x=(2±√8)/2∴x=1+√2 x=1-√24y^2 -(√2+8)y+ √2=0y=[(√2+8)±√(2+16√2+64-16√2)]/8y =[(√2+8)±√66]/8y...
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