直线y=kx+b与y=-5x+1平行,且过(2,1),则k=______,b=______.
人气:227 ℃ 时间:2020-06-20 10:42:49
解答
∵直线y=kx+b与y=-5x+1平行,
∴k=-5,
∵直线y=kx+b过(2,1),
∴-10+b=1,
解得:b=11.
故填-5、11.
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