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x-4=(x-4)^2用因式分解法 (5x-1)(2x+4)=3x+6 x^2+5=2根号5x
x-4=(x-4)^2
(5x-1)(2x+4)=3x+6
x^2+5=2根号5x
人气:497 ℃ 时间:2019-10-19 04:20:51
解答
x-4=(x-4)^2,(x-4)^2-(x-4)=0,(x-4)(x-4-1)=0,x=4或x=5(5x-1)(2x+4)=3x+610x²+20x-2x-4-3x-6=010x²+15x-10=02x²+3x-2=0(2x-1)(x+2)=0x=1/2或x=-2x^2+5=2根号5xx^2-2根号5x+5=0(x-根号5)²=...
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