因式分解:(1)2x^2-4x-3 (2)x^2-5x+5 解方程:(2x-1)^2-49=0
人气:416 ℃ 时间:2019-10-11 11:13:01
解答
(1)2x^2-4x-3=2(x^2-2x+1)-3-2=2(x-1)^2-5=[2^0.5(x-1)+5^0.5]*[2^0.5(x-1)-5^0.5]*(2)x^2-5x+5=x^2-5x+(5/2)^2-(5/2)^2+5=(x-2.5)^2-1.25=(x-2.5-0.5*5^0.5)*(x-2.5+0.5*5^0.5)解方程:(2x-1)^2-49=0 (2x-1)^2-7^...
推荐
猜你喜欢