已知x .y是正整数,且8/x+2/y=1,求x+y的最小值
人气：123 ℃ 时间：2020-03-31 11:41:33
解答
x+y=(x+y)*1=(x+y)(8/x+2/y)=10+2x/y+8y/x>=10+2*根号(2x/y*8y/x)=18
则x+y的最小值=18
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