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化简:(sin(α-3π)*cos(-α))/(tan(α-5π)*cos^2(α-5π)*tan(4π-α))
人气:281 ℃ 时间:2020-04-09 03:01:35
解答
tan(α-5π)*cos^2(α-5π)*tan(4π-α)= -tan^2α*cos^2α= -sin^2α
sin(α-3π)*cos(-α)= -sinα*cosα
原式= -sinα*cosα/(-sin^2α)= cotα
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