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请问:lim x->2/pal (lnsinx)/(pai-2x)^2
人气:156 ℃ 时间:2020-10-02 04:39:25
解答
lim (x->pai/2) (lnsinx)/(pai-2x)^2 (0/0)
=(L')=lim(x->pai/2)[cosx/sinx]/(8x-4pai)(0/0)
=(L')=lim(x->pai/2)-sinx/[cosx(8x-4pai)+8sinx] (代入)
=-1/8
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