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利用分解因式计算(1)(a²-b²)/(a+b) (2)(x²-4x-5)/(x+1)
(3)(ax²-2ax-3a)/(x-3) (4)[(x+y)²-4xy]/(x-y)
人气:295 ℃ 时间:2020-06-26 02:08:44
解答
答:(1)(a²-b²)/(a+b)=(a-b)(a+b) /(a+b)=a-b(2)(x²-4x-5)/(x+1)=(x-5)(x+1)/(x+1)=x-5(3)(ax²-2ax-3a)/(x-3) =a(x²-2x-3)/(x-3)=a(x-3)(x+1)/(x-3)=a(x+1)(4)[(x+y)²...
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