因式分解x^6+2x^5+3x^4+4x^3+2x^1+2x+1
x^6+2x^5+3x^4+4x^3+2x^2+2x+1
人气：375 ℃ 时间：2019-10-11 02:07:30
解答
题肯定错了原式=x^3(x^3+2x^2+3x+4+3/x+2/x^2+1/x^3)=x^3(x^3+1/x^3+2x^2+2/x^2+4+3x+3/x)=x^3[(x+1/x)(x^2-1+1/x^2)+2(x+1/x)^2+3(x+1/x)]=x^3(x+1/x)(x^2-1+1/x^2+2x+2/x+3)=x^3(x+1/x)(x^2+2+1/x^2+2x+2/x)=x^3(x...
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