∵2x²=(√2+1-x)²∴两边同时开方：√2x=√2+1-x或-√2x=√2+1-x当√2x=√2+1-x时,(√2+1)x=√2+1,x=1当-√2x=√2+1-x时,(√2-1)x=-√2-1,x=(-√2-1)/(√2-1)=-(√2+1)²=-3-2√2∴方程的解为：x=1或x=...