sina-cosa=(根号2)/5,求sin(π+a)+cos(π-a)=?
人气:190 ℃ 时间:2019-10-23 03:54:02
解答
(sina-cosa)²
=sin²a+cos²a-2sinacosa
=1-2sinacosa
=2/25
2sinacosa=23/25
(sina+cosa)²
=1+2sinacosa
=48/25
sin(π+a)+cos(π-a)
=-sina-cosa
=±4√3/5
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