先求得F2(根号3,0) 设A(x1,y1) B(x2,y2)
△ABF2的面积=OF2*(|y1|+|y2|)/2,其中y1,y2为A和B的纵坐标.设y1>0,y2根号3*(y1-y2)/2=根号3
=>y1-y2=2
=>y1=1
=>x1=0
=>直线为y轴 x=0.