[f(x)/f '(x)]'=[f '²(x)-f(x)f ''(x)]/f '²(x)=1-f(x)f ''(x)/f '²(x)因此题目中的被积函数为：[f(x)/f'(x)-f^2(x)f"(x)/f'^3(x)]=[f(x)/f '(x)][1-f(x)f ''(x)/f '²(x)]=[f(x)/f '(x)][f(x)/f...