y=根号3*cosx/(2+sinx)√3*cosx=Y（2+sinx）Ysinx-√3*cosx=-2Y（Y²+3）sin(x-θ)=-2ysin(x-θ)=-2y/(Y²+3)由于：|sin(x-θ)|≤1所以：|-2y/(Y²+3)|≤1解得：|y|≤1所以：y=根号3*cosx/(2+sinx)的值...