如果是一个式子就是
Ba2+ +2OH- +H+ +SO42-=BaSO4↓+H2O+OH-
化简Ba2+ +OH- +H+ +SO42-=BaSO4↓+H2O
分部写如下,因为HSO4-为二元强酸的带H酸根,可电离所以分部写一半会写成H+ +SO42-
足量Ba(OH)2,OH-应该是过量
NaHSO4 + Ba(OH)2=BaSO4↓ +H2O +NaOH
Ba2+ +2OH- +HSO4- =BaSO4↓+H2O +OH-
H+ +SO42- +Ba2+ +2OH- =BaSO4↓+H2O+OH-
H+ +SO42- +Ba2+ +OH- =BaSO4↓+H2O
如果是NaHSO4过量
2NaHSO4 + Ba(OH)2 = BaSO4↓ +2H2O +Na2SO4
Ba2+ +2OH- +2HSO4- =BaSO4↓ +SO42- +2H2O
2H+ +2SO42- +Ba2+ +2OH- =BaSO4↓+2H2O +SO42-
2H+ +SO42- +Ba2+ +2OH- =BaSO4↓+2H2O