5a^2-2ab-2b^2-(4a^2-2ab+b^2)要过程5a^2-2ab-2b^2-(4a^2-2ab+b^2)=[-3^2_数学解答

5a^2-2ab-2b^2-(4a^2-2ab+b^2)要过程
5a^2-2ab-2b^2-(4a^2-2ab+b^2)=
[-3^2*2-(-2)^3*3-4*/6/]/(-3)^2=
[-3^2*2-(-2)^3*3-4*/-6/]/(-3)^2,刚刚打错了是-6的绝对值

人气：429 ℃　时间：2020-02-02 07:04:13

解答

=5a^2-2ab-2b^2-4a^2+2ab-b^2=a^2-3b^2
=(-18+24-24)/9=-2