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数学
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(6x+12)/(x^2+4x+4)+(x^2)/(x^2-4)=(x^2-4)/(x^2-4x+4)
人气:378 ℃ 时间:2020-06-09 11:01:38
解答
6(x+2)/(x+2)²+x²/(x+2)(x-2)=(x+2)(x-2)/(x-2)²6/(x+2)+x²/(x+2)(x-2)=(x+2)/(x-2)两边乘(x+2)(x-2)6x-12+x²=x²+4x+46x-12=4x+4x=8经检验,x=8是方程的解
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