(3X^2-10X-7)/(X-2)≥0
等于于,3X^2-10X-7≥0,x-2>0,解得x≥（5+2√6）/3
当3X^2-10X-7＜0,x-2＜0,解得（5-2√6）/3＜x＜2
所以原不等式的解集是x≥（5+2√6）/3或（5-2√6）/3＜x＜2